High Five

Easy

Company Tags

Given a list of the scores of different students, items, where items[i] = [ID_i, score_i] represents one score from a student with ID_i, calculate each student's top five average.

Return the answer as an array of pairs result, where result[j] = [ID_j, topFiveAverage_j] represents the student with ID_j and their top five average. Sort result by ID_j in increasing order.

A student's top five average is calculated by taking the sum of their top five scores and dividing it by 5 using integer division.

Example 1:

Input: items = [[1,91],[1,92],[2,93],[2,97],[1,60],[2,77],[1,65],[1,87],[1,100],[2,100],[2,76]]

Output: [[1,87],[2,88]]

Explanation:
The student with ID = 1 got scores 91, 92, 60, 65, 87, and 100. Their top five average is (100 + 92 + 91 + 87 + 65) / 5 = 87.
The student with ID = 2 got scores 93, 97, 77, 100, and 76. Their top five average is (100 + 97 + 93 + 77 + 76) / 5 = 88.6, but with integer division their average converts to 88.

Example 2:

Input: items = [[1,100],[7,100],[1,100],[7,100],[1,100],[7,100],[1,100],[7,100],[1,100],[7,100]]

Output: [[1,100],[7,100]]

Constraints:

  • 1 <= items.length <= 1000
  • items[i].length == 2
  • 1 <= ID_i <= 1000
  • 0 <= score_i <= 100
  • For each ID_i, there will be at least five scores.


Company Tags

items =