802. Find Eventual Safe States - Explanation
Prerequisites
Before attempting this problem, you should be comfortable with:
- Graph Representation - Understanding adjacency lists and how directed graphs are stored
- Depth-First Search (DFS) - Traversing graphs and detecting cycles using visited states
- Memoization - Caching results to avoid redundant computation during graph traversal
- Topological Sort - Understanding Kahn's algorithm and processing nodes by in-degree/out-degree
1. Depth First Search
Intuition
A node is safe if every path starting from it eventually leads to a terminal node (a node with no outgoing edges). Conversely, a node is unsafe if it can reach a cycle. We can use DFS with memoization to determine safety: initially mark a node as unsafe when we start exploring it (to detect cycles), then mark it safe only if all its neighbors are safe. If we revisit a node marked unsafe during exploration, we have found a cycle.
Algorithm
- Create a hash map
safeto track each node's safety status. - For each node, run DFS:
- If the node's status is already known, return it.
- Mark the node as
false(unsafe) initially to detect cycles. - Recursively check all neighbors. If any neighbor is unsafe, return
false. - If all neighbors are safe, mark the current node as
true(safe).
- Collect all nodes where
dfs(node)returnstrueand return them in order.
class Solution:
def eventualSafeNodes(self, graph: List[List[int]]) -> List[int]:
n = len(graph)
safe = {}
def dfs(node):
if node in safe:
return safe[node]
safe[node] = False
for nei in graph[node]:
if not dfs(nei):
return safe[node]
safe[node] = True
return safe[node]
res = []
for node in range(n):
if dfs(node):
res.append(node)
return resTime & Space Complexity
- Time complexity:
- Space complexity:
Where is the number of vertices and is the number of edges in the given graph.
2. Topological Sort (Kahn's Algorithm)
Intuition
Think of safe nodes as those that can reach terminal nodes. If we reverse the edge directions, safe nodes are those reachable from terminal nodes. Using Kahn's algorithm on this reversed perspective: terminal nodes have zero out-degree in the original graph. We start from these terminal nodes and work backward, removing edges. Any node whose out-degree reaches zero is safe because all its paths lead to already-confirmed safe nodes.
Algorithm
- Build a reverse adjacency list (
parents) and track the out-degree of each node. - Add all terminal nodes (out-degree =
0) to a queue. - Process nodes from the queue:
- For each parent of the current node, decrement its out-degree.
- If a parent's out-degree becomes
0, add it to the queue.
- After processing, all nodes with out-degree
0are safe. - Return the safe nodes in sorted order.
class Solution:
def eventualSafeNodes(self, graph: List[List[int]]) -> List[int]:
n = len(graph)
outdegree = [0] * n
parents = [[] for _ in range(n)]
queue = deque()
for node in range(n):
outdegree[node] = len(graph[node])
if outdegree[node] == 0:
queue.append(node)
for nei in graph[node]:
parents[nei].append(node)
while queue:
node = queue.popleft()
for parent in parents[node]:
outdegree[parent] -= 1
if outdegree[parent] == 0:
queue.append(parent)
res = []
for node in range(n):
if outdegree[node] <= 0:
res.append(node)
return resTime & Space Complexity
- Time complexity:
- Space complexity:
Where is the number of vertices and is the number of edges in the given graph.
Common Pitfalls
Confusing Visited with Safe Status
A node being visited during DFS does not mean it is safe. You need separate tracking for "currently being explored" (to detect cycles) and "confirmed safe" (all paths lead to terminal nodes). Mixing these states causes incorrect cycle detection or premature safety classification.
Not Returning Results in Sorted Order
The problem requires returning safe nodes in ascending order. If you collect nodes as they are confirmed safe during DFS, the order depends on traversal order, not node indices. Either sort the result at the end or iterate through nodes 0 to n-1 and check each one's safety status.
Incorrectly Handling Nodes with No Outgoing Edges
Terminal nodes (nodes with no outgoing edges) are always safe by definition. In the topological sort approach, these nodes have out-degree 0 and should be the starting points. In DFS, they should immediately return true without further recursion.